Question

x elevado a 2 -2x-3=0 qual o valor do 0 por favor me ajudem 

Answer 1

Resolvendo por Bhaskara, temos:
x²-2x-3=0
a= 1 b= -2 c=-3
-(-2)±√(-2)²-4.1.(-3)/2
2±√4-(-12)/2
2±√16/2
2±4/2
x'= 3
x''= -1
S:[-1,3]

Answer 2

$x^{2} -2x-3=0= \Delta= b^{2} -4.a.c= \Delta= -2^{2} -4.1.(-3)= \Delta=4+12=16  x^{1} =-+(-2) \sqrt{16} /2=2+4/2=6/2=3 x^{2} =-+ (-2) \sqrt{16} /2=2-4/2=-2/2=-1$


S{3,-1}