Question

X = -b + raiz quadrada b²-4. A. C para a = 1; b =-12.

Answer 1

$x = - b + \sqrt{ {b}^{2} - 4ac }$

$x = - - 12 + \sqrt{ { - 12}^{2} - 4.1. - 12 }$

$x = 12 + \sqrt{ - 12. - 12 + 48}$

$x = 12 + \sqrt{144 + 48}$

$x = 12 + \sqrt{192}$

$x = 12 + 13.86$

x= 25, 86