X ao quadrado = X+12.
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x² = x + 12
x² - x - 12 = 0
Δ = b²−4ac
Δ = (−1)²−4⋅1⋅−12
Δ = 1 + 48
Δ = 49
![x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\x = \dfrac{-(-1) \pm \sqrt{49}}{2*1}\\ \\ \\x = \dfrac{1 \pm 7}{2}\\ \\ \\x' = \dfrac{1 + 7}{2}\\ \\ \\x' = \dfrac{8}{2}\\ \\ \\x' = 4\\ \\ \\x'' = \dfrac{1 - 7}{2}\\ \\ \\x'' = \dfrac{-6}{2}\\ \\ \\x'' = -3
x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\x = \dfrac{-(-1) \pm \sqrt{49}}{2*1}\\ \\ \\x = \dfrac{1 \pm 7}{2}\\ \\ \\x' = \dfrac{1 + 7}{2}\\ \\ \\x' = \dfrac{8}{2}\\ \\ \\x' = 4\\ \\ \\x'' = \dfrac{1 - 7}{2}\\ \\ \\x'' = \dfrac{-6}{2}\\ \\ \\x'' = -3](https://tex.z-dn.net/?f=x+%3D+%5Cdfrac%7B-b+%5Cpm+%5Csqrt%7B%5CDelta%7D%7D%7B2%2Aa%7D%5C%5C+%5C%5C+%5C%5Cx+%3D+%5Cdfrac%7B-%28-1%29+%5Cpm+%5Csqrt%7B49%7D%7D%7B2%2A1%7D%5C%5C+%5C%5C+%5C%5Cx+%3D+%5Cdfrac%7B1+%5Cpm+7%7D%7B2%7D%5C%5C+%5C%5C+%5C%5Cx%27+%3D+%5Cdfrac%7B1+%2B+7%7D%7B2%7D%5C%5C+%5C%5C+%5C%5Cx%27+%3D+%5Cdfrac%7B8%7D%7B2%7D%5C%5C+%5C%5C+%5C%5Cx%27+%3D+4%5C%5C+%5C%5C+%5C%5Cx%27%27+%3D+%5Cdfrac%7B1+-+7%7D%7B2%7D%5C%5C+%5C%5C+%5C%5Cx%27%27+%3D+%5Cdfrac%7B-6%7D%7B2%7D%5C%5C+%5C%5C+%5C%5Cx%27%27+%3D+-3%0A)
S = {4, -3}
x² - x - 12 = 0
Δ = b²−4ac
Δ = (−1)²−4⋅1⋅−12
Δ = 1 + 48
Δ = 49
S = {4, -3}
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ThiiagoMiranda1:
como ?
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