Question

X ao quadrado +(x+1)=481

Answer 1

$x^2+(x+1)~=~481\\\\\\x^2+x+1-481~=~0\\\\\\\boxed{x^2+x-480~=~0}\\\\\\Aplicando~Bhaskara\\\\\\\Delta~=~1^2-4.1.(-480)~=~1+1920~=~\boxed{1921}\\\\\\x'~=~\dfrac{-1+\sqrt{1921}}{2~.~1}~=~\boxed{\dfrac{-1+\sqrt{1921}}{2}}\\\\\\x''~=~\dfrac{-1-\sqrt{1921}}{2~.~1}~=~\boxed{\dfrac{-1-\sqrt{1921}}{2}}$