Question

x ao quadrado mais 6x +8=0

Answer 1

X ^2 + 6x + 8 = 0, para resolver aplicaremos bhaskara.


Delta = b^2 - 4.a.c
6^2 - 4 . 1 . 8
36 - 4 . 8
36 - 32
4

X = -b +/- raiz de delta
------------------------
2. a

X = -6 +/- 2
----------
2

X1 = -6 + 2
---------
2
X1 = 4/2
X1 = 2



X2 = -6 - 2
--------
2
X2 = -8/2
X2 = -4