Question

x ao quadrado -5×+6=0 me ajudem.

Answer 1

$x^{2} -5x+6=0\\ \\ \Delta=(-5)^2-4.1.6=25-24=1 \\ \\ x=\frac{5 \pm \aqrt1}{2}=\frac{5 \pm 1}{2}\\ \\ x_1=\frac{5-1}{2}=2\\ \\ x_2=\frac{5+1}{2}=3$

Answer 2

OLÁ
 
 X²-5X+6=0
 Δ=B²-4.A.C
 a=1,b=-5 ,c=6
Δ=b²-4.a.c
Δ=(-5)²-4.1.6
Δ=25-24
Δ=1

 x=-b+-√Δ/2.a
x1=-(-5)+1/2.
x1=5+1/2 
X1=3

x1=  5-1/2

x2=4/2=2

 S=(2,3)