Question

x ao quadrado + 2x -3 =0 como posso resolver

Answer 1

Olá, bom dia!

Utilizando a fórmula de Bhaskara.

$x^2+2x-3=0\\\\Coeficientes:\;a=1,\;b=2\;e\;c=-3\\\\\Delta=b^2-4ac\\\Delta=2^2-4\cdot1\cdot(-3)\\\Delta=4+12\\\Delta=16\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-2\pm\sqrt{16}}{2\cdot1}\\\\x=\dfrac{-2\pm4}{2}\\\\x_1=\dfrac{-2+4}{2}=\dfrac{2}{2}=1\\\\x_2=\dfrac{-2-4}{2}=\dfrac{-6}{2}=-3$

Espero ter ajudado.

Bons estudos! :)

Answer 2

Oi...

x² + 2x - 3 = 0

Coeficientes

a = 1 ; b = 2. c = - 3

Calculando delta

Δ = b² - 4.a.c

Δ = 2² - 4. 1. - 3

Δ = 4 + 12

Δ = 16

Há 2 raízes reais

Aplicando Bhaskara

x = - b ± √Δ/2.a

x' = - (+2 + √16)/2.1

x' = - 2 + 4/2

x' = 2/2

x' = 1

x" = - ( + 2 - 4)/2.1

x" = - 2 - 4/2

x" = - 6/2

x" = - 3

S = {x' = 1 e x" = - 3}

Espero ter ajudado.