Question

x=a raiz quadrada de 7 sobre 3 +raiz quadrada de 6 sobre 4+ raiz quadrada de 16, então x é igual

Answer 1

$\boxed{\begin{array}{l}\rm x=\dfrac{\sqrt{7}}{3}+\dfrac{\sqrt{6}}{4+\sqrt{16}}\\\\\rm x=\dfrac{\sqrt{7}}{3}+\dfrac{\sqrt{6}}{4+4}\\\\\rm x=\dfrac{\sqrt{7}}{3}+\dfrac{\sqrt{6}}{8}\end{array}}$