Question

(x+6)/3-(2x-3)/6=(x+1)/4

Answer 1

$\dfrac{(x+6)}{3}-\dfrac{(2x-3)}{6}=\dfrac{(x+1)}{4}$

$\dfrac{[2(x+6)-(2x-3)]}{6}=\dfrac{(x+1)}{4}$

$\dfrac{(2x+12-2x+3)}{6}=\dfrac{(x+1)}{4}$

$\dfrac{15}{6}=\dfrac{(x+1)}{4}$

$\dfrac{5}{2}=\dfrac{(x+1)}{4}$

$20=2(x+1)$

$2x+2=20$

$2x=18$

$x=9$