Question

-x-5+4x=-7x+6x+15, (x-1)/2+(x-2)/3=(x-3)/4

Answer 1

$-x-5+4x=-7x+6x+15 \\ -x+4x+7x-6x=15+5 \\ 4x=20 \\ x= \frac{20}{4} \\ \boxed{x=5}$



$\frac{x-1}{2}+ \frac{x-2}{3}= \frac{x-3}{4} \\ \\ \frac{6(x-1)+4(x-2)}{\not12}= \frac{3(x-3)}{\not12} \\ \\ 6(x-1)+4(x-2)}= 3(x-3)} \\ 6x-6+4x-8=3x-9 \\ 6x+4x-3x=-9+6+8 \\ 7x=5 \\\boxed{ x= \frac{5}{7}}$