Question

X + 4 x -1, para x= 1,333...

Answer 1

$1,333...=1+0,333...=1+\frac{1}{3} =\frac{3}{3} +\frac{1}{3} =\frac{4+1}{3} =\frac{4}{3}$

$x+4x-1=\frac{4}{3} +4\cdot\frac{4}{3}-1=\frac{4}{3} +\frac{16}{3}-1=\frac{4}{3} +\frac{16}{3}-\frac{3}{3} =\frac{4+16-3}{3} =\frac{17}{3}$