Question

x^4-12x^2-64=0 me ajude porfavor

Answer 1

(x²)²-12(x²)-64=0
x²=y
y²-12y-64=0
Δ=400
(12+20)/2.1=16
(12-20)/2.1=-4-
x²=y
x=√16=4
x=√-4=?