Question

(X+3)²=1 COM DELTA E BHASKARA PF <3

Answer 1

(x+3)²=1
(x=3).(x=3)=1
x²+3x+3x+9=1
x²+6x+9-1=0
x²+6x+8=0
a=1; b=6; c=8

Achando o Delta (d).
d=b²-4ac
d=6²-4.1.8
d= 36-32
d=4
x=-b±√d / 2.a
x=-6±√4 / 2.1±
x=-6±2 / 2
x'=-6+2 / 2
x'=-4/2
x'= -2
x"=-6-2 / 2
x"=-8 / 2
x"= -4
S={-2 , -4}

Espero ter ajudado.