Question

x^2-8x+p=0

x'=6

Qual o valor de p?​

Answer 1

$\mathsf{x^2-8x+p=0}\\\mathsf{6^2-8.6+p=0}\\\mathsf{36-48+p=0}\\\mathsf{-12+p=0}$

$\huge\boxed{\boxed{\boxed{\boxed{\mathsf{p=12}}}}}$

Answer 2

Explicação passo-a-passo:

x² - 8x + p = 0

Substituindo x por 6:

6² - 8.6 + p = 0

36 - 48 + p = 0

p = 48 - 36

p = 12