Question

x^2 + 8 x + 16 = 0 me ajudem

Answer 1

x^2 + 8x + 16 = 0
Δ = b^2 - 4.a.c 
Δ = 8^2 - 4 . 1 . 16 
Δ = 64 - 4. 1 . 16 
Δ = 0

Há 1 raiz real.

Neste caso, x' = x'':

x = (-b +- √Δ)/2a

x' = (-8 + √0)/2.1   
x'' = (-8 - √0)/2.1

x' = -8 / 2   
x'' = -8 / 2

x' = -4   
x'' = -4

Answer 2

x2 + 8x + 16 =0
∆ = 64 - 64
∆ = 0
x = - b / 2a
x = - 8 / 2
x = - 4