Question

 x^{2} - 3x + 2 = 0[/tex]

Answer 1

Δ=$b^{2} -4ac$
Δ=$(-3)^{2} -4.1.2$
Δ=9-8=1
x=$\frac{-b \sqrt{delta} }{2.a}$
x=$\frac{-(-3) \sqrt{1}}{2.1}$
x'=$\frac{3+1}{2} = \frac{4}{2} =2$
x''=$\frac{3-1}{2} = \frac{2}{2} =1$