Question

x^2+2x-4x=0


x^2-8x+7=0


x^2-6x+8=0


x^2-x-20=0


reduzi e aplicar a formmula de baskara .

Answer 1

1) x²+2x-4x= 0

x²-2x=0

∆=(-2)²-4.1.0

∆= 4-0

∆= 4

x= 2±2/2

x'= 4/2 = 2

x"= 0/2 = 0

2) x²-8x+7= 0

∆= (-8)²-4.1.7

∆= 64-28

∆= 36

x= 8±6/2

x= 14/2 = 7

x= 2/2 = 1

3) x²-6x+8= 0

∆= (-6)²-4.1.8

∆= 36-32

∆= 4

x= 6±2/2

x'= 8/2 = 4

x"= 4/2 = 2

4) x²-x-20= 0

∆= (-1)²-4.1.-20

∆= 1+80

∆= 81

x= 1±9/2

x'= 10/2 = 5

x"= -8/2 = -4

espero ter ajudado