Question

X + 1 = X² Quais os possíveis valores de X?

Answer 1

x+1=x²

x²-x-1=0

a=1
b=-1
c=-1

Δ=b²-4ac
Δ=(-1)²-4(1)(-1)
Δ=1 +4
Δ=5

$x=- \frac{b\pm \sqrt{\triangle} }{2a} = \frac{-(-1)\pm \sqrt{5} }{2} = \frac{1\pm \sqrt{5} }{2} \\ \\ x'= \frac{1+ \sqrt{5} }{2} \\ \\ x"= \frac{1- \sqrt{5} }{2}$