Question

(x+1).(x.2)=-7x-10 resolva em bhaskara pfv eu preciso rapido!!!to em desespero

Answer 1

(x +1).(x . 2) = -7x - 10

(x + 1).(2x) = -7x - 10
2x² + 2x = -7x - 10
2x² + 2x + 7x + 10 = 0
2x² + 9x + 10 = 0

===
$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}$

Encontrar o valor de Δ

Δ = b²−4ac
Δ = (9)²−4⋅2⋅10
Δ = 81−80
Δ = 1


$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\ x = \dfrac{-9 \pm \sqrt{1}}{2*2}\\ \\ \\ x = \dfrac{-9 \pm 1}{4}\\ \\ \\ x' = \dfrac{-9 + 1}{4}\\ \\ \\ x' = \dfrac{-8}{4}\\ \\ \\ x' = -2\\ \\ \\ x'' = \dfrac{-9 - 1}{4} \\ \\ \\ x'' = \dfrac{-10}{4}\\ \\ \\ x'' = \dfrac{-5}{2}$

$S = \{~2, ~ -\dfrac{5}{2} ~\}$