^x+1 raiz de 2 elevado a x-1=2????
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Olá Jujuba,
![(\sqrt[x+1]{2})^{x-1}=2~~~~.\\
(2^{ \tfrac{1}{x+1}})^{x-1}=2^1\\
\not2^{ \tfrac{x-1}{x+1}}=\not2^1\\\\
\dfrac{x-1}{x+1}=1\\\\
x-1=x+1\\
x-x=1+1~~(sem~solucao)\\](https://tex.z-dn.net/?f=+%28%5Csqrt%5Bx%2B1%5D%7B2%7D%29%5E%7Bx-1%7D%3D2%7E%7E%7E%7E.%5C%5C%0A%282%5E%7B+%5Ctfrac%7B1%7D%7Bx%2B1%7D%7D%29%5E%7Bx-1%7D%3D2%5E1%5C%5C%0A%5Cnot2%5E%7B+%5Ctfrac%7Bx-1%7D%7Bx%2B1%7D%7D%3D%5Cnot2%5E1%5C%5C%5C%5C%0A+%5Cdfrac%7Bx-1%7D%7Bx%2B1%7D%3D1%5C%5C%5C%5C%0Ax-1%3Dx%2B1%5C%5C%0Ax-x%3D1%2B1%7E%7E%28sem%7Esolucao%29%5C%5C%0A++++ "(\sqrt[x+1]{2})^{x-1}=2~~~~.\\
(2^{ \tfrac{1}{x+1}})^{x-1}=2^1\\
\not2^{ \tfrac{x-1}{x+1}}=\not2^1\\\\
\dfrac{x-1}{x+1}=1\\\\
x-1=x+1\\
x-x=1+1~~(sem~solucao)\\")
Tenha ótimos estudos ;D
Tenha ótimos estudos ;D
jujuba054:
Muito Obrigada Korvo!! :D
NDS^^
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