Matemática, perguntado por aepsalamanca, 11 meses atrás

x-1=5-x/4 ?

x+x/2=15 ?

8x/3=2x-9 ?

x/2+3/4=1/6 ?

(x-1)/2 + (x-3)/3=6 ?

(5x-7) /2 = 1/2+x ?

(2x-1) /3 = x - (x - 1) /5 É pra hj vlw!!

Soluções para a tarefa

Respondido por FilipePhysic
1

Equação com Fração

x - 1 = 5 - \frac{x}{4} \to \mahsf{mmc~de~4}\\ \\ \frac{4x - 4 = 20 - x}{4} \\ \\ 4x-4=20-x\\ 4x+x=20+4\\5x = 24\\ \\ \boxed{x = \frac{24}{5}}

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x + \frac{x}{2} = 15 \to \mathsf{mmc~de~2}\\ \\ \frac{2x + x = 30}{2} \\ \\ 2x + x = 30\\ 3x = 30\\ \\ x = \frac{30}{3}\\ \\ \boxed{ x = 10}

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\frac{8x}{3} = 2x - 9 \to \mathsf{mmc~de~3}\\ \\ \frac{8x = 6x - 27}{3} \\ \\ 8x = 6x - 27\\ 8x - 6x = -27 \\ \\ 2x = -27\\ \\ \boxed{x = \frac{-27}{2}}

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\frac{x}{2} + \frac{3}{4} = \frac{1}{6} \to \mathsf{mmc~de~2,4,6}\\ \\ 2,4,6|2\\ 1,2,3|2\\ 1,1,3|3\\ 1,1,1|1 ~~~~~3.2.2 = 12\\\\ \frac{6x + 9 = 2}{12} \\ \\ 6x + 9 = 2\\6x = 2 - 9 \\6x = - 7 \\\\ \\ \boxed{x = \frac{-7}{6}}

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\frac{(x-1)}{2} + \frac{(x-3)}{3} = 6 \to \mathsf{mmc~de~3,2 = 3.2 = 6 } \\ \\ \frac{3x-3+2x-6 = 36}{6} \\ \\ 3x-3+2x-6=36\\ 3x+2x = 36 + 6-3\\ 5x = 39\\ \\ \boxed{x = \frac{39}{5} }

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\frac{(5x-7)}{2} = \frac{1}{2} + x \to \mathsf{mmc~de~2~= 2} \\ \\ \frac{5x-7 = 2 + 2x}{2} \\ \\ 5x - 7 = 2 + 2x\\ 5x-2x = 2 + 7 \\ 3x = 9\\ \\ x = \frac{9}{3} \\ \\ \boxed{x = 3}

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\frac{(2x-1)}{3} = x - \frac{x-1}{5} \to \mathsf{mmc~de~3,5 = 3.5=15} \\ \\ \frac{10x-5 = 15x - 3x-3}{15} \\ \\ 10x-5=15x-3x-3\\ 10x-15x-3x = -3 + 5\\-8x = 2\\ \\ x = \frac{2}{-8}:2 = \boxed{x = \frac{-1}{4}}


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