Question

Write the standard form of the equation of the circle shown below.

(2,-1) (4,-1)

A. (x + 4)2 + y - 12 = 2
B. (x - 4)2 + y + 12 = 2
C. (x + 2)2 + y - 12 = 4
D. (x - 2)2 + y + 12 = 4

Answer 1

Explanation:

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.

If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point. If a circle is tangent to the y-axis at (0,3), this means it touches the y-axis at that point. Given these two points, we can determine the center and the radius of the circle. The center of the circle must be equidistant from any of the points on the circumference. This means that both (0,3) and (3,0) are the same distance from the center. If we draw these points on a coodinate plane, it becomes apparent that the center of the circle must be (3,3). This point is exactly three units from each of the given points, indicating that the radius of the circle is 3.

When we input this information into the formula for a circle, we get (x – 3)2 + (y – 3)2 = 9.

CORRECT ANSWER WAS C

Answer 2

the correct awnser is C

(i'm a brazillian so i dont speak english very well,so idk if I wrote it right)