Which is contains more molecules, 6.35 x 10^23 molecules of sodium hydroxide or 44.32 g of sodium hydroxide?
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Resposta:
44,32 g
Explicação:
N=nxNA
NA=constant=6,022 x 10 ^23
We need to know how many molecules are in 44,32g of sodium hidroxide.
M(NaOH)=22,99+16,00+1,01= 40g/mol
n=m/M
<=>n=44,32/40
<=>n=1,108 mol
N = n x NA = 1,108 x 6,022 X 10^23 = 1 x 10^24 molecules
1 x 10^24 > 6,022 x 10 ^23
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