Question

What is the sum of all values of m that satisfy 2m(squared) - 16m + 8 = 0 ?

Answer 1

Resposta:

Explicação passo-a-passo:

2m^2 - 16m + 8 = 0

a = 2

b = -16

c = 8

Bhaskara

Δ = b^2-4.a.c

Δ = -10^2-4.2.8

Δ = 100-64

Δ = 36

$\frac{-b+or-\sqrt{Δ}}{2.a}$

x' =$\frac{ -(-10)+\sqrt{36}}{2.2}$

x' = 10 + 36 / 4

x' = 46/4

simplifies for 2

x'=23/2

x" = $\frac{ -(-10)-\sqrt{36}}{2.2}$

x" = 10-6/4

x" = 4/4 => 1