Question

- What is the mass of the precipitate formed when 12.0 mL of 0.150 M NaCl is added to 25.00 mL of

a 0.0500 M AgNO3 solution?

a​

Answer 1

Given Molarity of NaCl ,M = 0.15 M Volumeof NaCl V = 12 mL = 0.012 L No . of moles of NaCl n = M*V = 0.0018 moles Simillarly No . of moles of AgNO3 is n' = Molarity * Volume inL

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