Question

Vértice da parábola

y=x²-2x+1

Answer 1

∆ = b² - 4 . a . c
∆ = (-2)² - 4 . 1 . 5
∆ = 4 - 20
∆ = -16

xV = -b / 2a
xV = -(-2) / (2 . 1)
xV = 2 / 2
xV = 1

yV = -∆ / 4a
yV = -(-16) / (4 . 1)
yV = 16 / 4
yV = 4
Logo, as coordenadas do vértice são:
V(1, 4)

Answer 2

xv = -b/2a = -(-2)/2.1 = 2/2 = 1
∆ = b^2-4.a.c
∆ = (-2)^2-4.1.1
∆ = 4-4
∆ = 0

yv = -∆/4a
yv = 0/4
yv = 0

v (1,0)