Question

Verifique se a expressão √b² - 4ac representa um número real quando a= 10, b= -1 e c= -3

Answer 1

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}a = 10\ ;\ b=-1;\ c=-3\ \\\\\sqrt{b^2-4ac} = \\\\\sqrt{(-1)^2-4*10*(-3)} = \\\\\sqrt{1+120} = \\\\\sqrt{121} = \\\\11\\\\ \boxed{\boxed{R:\ 11\ \in\ \mathbb{R}}}\end{array}\right$

Espero ter ajudado. =^.^=