Question

vcs sabem como resolver essa conta de delta

6ײ-×-5=0

Answer 1

$6x^2-x-5=0 \\ \\ \Delta=(-1)^2-4.6.(-5)=1+120=121 \\ \\ x=\frac{1+\sqrt{121}}{2.6}=\frac{1+-11}{12} \\ \\ x_1=\frac{1-11}{12}=-\frac{10}{12}=-\frac{5}{6} \\ \\ x_2=\frac{1+11}{2.6}=\frac{12}{12}=1$

Answer 2

Δ = b² - 4ac
Δ = (-1)² - 4(6)(-5)
Δ = 1 + 120
Δ = 121

Depois de resolver delta você joga na fórmula de bhaskara

$x = \frac{-b+- \sqrt{121} }{2a}$

$x= \frac{-(-1)+-11}{2(6)}$


                                              $x'= \frac{1+11}{12}=\frac{12}{12}=1$
$x= \frac{1+-11}{12}$
                                              $x"= \frac{1-11}{12}= \frac{-10}{12}= \frac{-5}{6}$