Question

Vamos resolver o sistema:

Me ajudem, por favor!!!!!!!​

Answer 1

$\left \{ {{\log x-\log y=\log 2} \atop {4^{x+y}=512}} \right.$

$\left \{ {{\log(x/y) =\log 2} \atop {(2^2)^{x+y}=2^9}} \right.$

$\left \{ {{x/y=2 } \atop {2^{2x+2y}=2^9}} \right.$

$\left \{ {{x/y=2} \atop {2x+2y=9}} \right.$

$\left \{ {{x=2y} \atop {2x+2y=9}} \right.$

$\left \{ {{x-2y=0} \atop {2x+2y=9}} \right.$

$(x-2y)+(2x+2y)=0+9\\x-2y+2x+2y=9\\3x=9$

$x=\frac{9}{3}$

$x=3$

$x-2y=0$

$3-2y=0\\-2y=-3\\2y=3$

$y=\frac{3}{2}$