Question

valor de x em 1+ tg x = o

Answer 1

Qual intervalo?

Vou considerar...: 0 < x < 180°

$1+\tan\,x=0\\\\\tan\,x=-1\\\\\frac{\sin\,x}{\cos\,x}=-1\\\\\frac{\sin135^o}{\cos135^o}=-1\\\\\frac{0,70}{-0,70}=-1\\\\-1=-1$

 Logo, x = 135°; ou $x=\frac{3\pi}{4}$