VALE 10 PONTOOOOOOOSSSS
Dois dados sao lançados e observa-se a soma de suas faces.
a- quais são os possíveis resultados para esta soma?
b- qual é a probabilidade de cada resultado possível?
Soluções para a tarefa
(a) Seja o par (x,y) as possibilidades dos de ocorrer esse resultado, então
(1,1)=2
(1,2);(2,1)=3
(1,3);(3,1);(2,2)=4
(1,4);(4,1);(2,3);(3,2)=5
(1,5);(5,1);(2,4);(4,2);(3,3)=6
(1,6);(6,1);(2,5);(5,2);(4,3);(3,4)=7
(2,6);(6,2);(3,5);(5,3);(4,4)=8
(3,6);(6,3);(4,5);(5,4)=9
(4,6);(6,4);(5,5)=10
(6,5);(5,6)=11
(6,6)=12
(b)
(1,1)=2 => P=(1/6)(1/6)=1/36
(1,2);(2,1)=3 => P=(1/6)(1/6)+(1/6)(1/6)=2/36
(1,3);(3,1);(2,2)=4 => P=(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)=3/36
(1,4);(4,1);(2,3);(3,2)=5 => (1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)=4/36
(1,5);(5,1);(2,4);(4,2);(3,3)=6 =>(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)=5/36
(1,6);(6,1);(2,5);(5,2);(4,3);(3,4)=7 => (1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)=6/36
(2,6);(6,2);(3,5);(5,3);(4,4)=8 => (1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)=5/36
(3,6);(6,3);(4,5);(5,4)=9 => (1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)=4/36
(4,6);(6,4);(5,5)=10 => (1/6)(1/6)+(1/6)(1/6)+(1/6)(1/6)=3/36
(6,5);(5,6)=11 => (1/6)(1/6)+(1/6)(1/6)=2/36
(6,6)=12 => (1/6)(1/6)=1/36