Question

V16 -(2/3)-² + (2/3 . 1/2)=

Answer 1

    $\sqrt{16} -(\frac{2}{3})^{-2}+(\frac{2}{3}\times\frac{1}{2})=$

$=4 -(\frac{2}{3})^{-1\times2}+\frac{2\times1}{3\times2}=$

$=4 -[(\frac{2}{3})^{-1}]^2+\frac{2}{6}=$

$=4 -(\frac{3}{2})^2+\frac{1}{3}=$

$=4 -\frac{3^2}{2^2}+\frac{1}{3}=$

$=4 -\frac{9}{4}+\frac{1}{3}=$

$=\frac{4\times12}{12}-\frac{9\times3}{4\times3}+\frac{1\times4}{3\times4}=$

$=\frac{48}{12}-\frac{27}{12}+\frac{4}{12}=$

$=\frac{48-27+4}{12}=$

$=\frac{21+4}{12}=$

$=\frac{25}{12}$