Question

utilizando o teorema de pitagoras determine o valor de x nos triangulos retângulos 3x 4x .20

Answer 1

hipotenusa⇒20  ( a )
cateto⇒3x  (b)
cateto⇒4x  (c)

a²=b²+c²

20²=(3x)²+(4x)²
9x²+16x²=400
25x²=400
x²=400÷25
x²=16
x=√16
x=4

Answer 2

hi i don't speak english could translate for me to help you i'm using the cell phone of a relative of mine who is brazilian could translate for me to answer i don't speak and i don't write very well in portuguese but i'm learning ^^ hope you understand this well please answer me to help you :)