Question

utilizando a tabela acima, encontre o valor dos logaritmos: a)log 4 b) log 40 c) log 400 d) blog 9 e) log 9000 f) log 14 g) log 140 h) log 15 i) log 45​ obs: é pra calcular os logaritmos e encontrar seu valor

Answer 1

O valor dos logaritmos é:

a) log 4 = log(2.2) = log 2 + log 2 = 0,30103 + 0,30103 = 0,60206

b) log 40 = log (2.20) = log 2 + log 20 = 0,30103 + 1,30103 = 1,60206

c) log 400 = log (2.200) = log 2 + log 200 = 0,30103 + 2,30103 = 2,60206

d) log 9 = log (3.3) = log 3 + log 3 = 0,47712 + 0,47712 = 0,95424

e) log 9000 = log (3.1000) = log 3 + log 1000 = 0,47712 + 3 = 3,47712

f) log 14 = log (2.7) = log 2 + log 7 = 0,30103 + 0,84509 = 1,14612

g) log 140 = log (2.7.10) = log 2 + log 7 + log 10 = 0,30103 + 0,84509 + 1 = 2,14612

h) log 15 = log (30:2) = log 30 - log 2 = 1,47712 - 0,30103 = 1,17609

i) log 45 = log (90:2) = log 90 - log 2 = 1,95424 - 0,30103 = 1,65321

pois,

> log 90 = log (9.10) = log 9 + log 10 = 0,95424 + 1 = 1,95424

Answer 2

Resposta:

a) log 4 log (2,2) = log 2 + log 2 0,30103 + 0,30103 = 0,60206 b) log 40 = log (2,20) = log 2 + log 20 0,30103 1,30103 1,60206 c ) log 400 = log (2.200) = log 2 + log 200 = 0,30103 + 230103 2,60206 d) log 9 log (3,3) = log 3 + log 3 0,47712 + 0,47712 0,95424 e) log 9000 log (3,1000) log 3 + log 1000 = 0,47712 + 3 3,47712 f) log 14 log (2,7) = log 2 + log 7 = 0,30103+ 0,84509 = 1,146129) log 140 = log (2.710) = log 2 + log + + log 10 = 0,30103 + 0,84509 +1 2.14612 h) log 15 = log (30: 2) = log 30 - Iog 2 = 1 , 47712- 0,30103 = 1,17609 i) log 45 = log (90: 2) = log 90 - log 2 1.95424 0,30103 = 1,65321 pois,> log 90 = log (9,10) = log 9 + log 10 = 0,95424 + 1 1,95424