Question

utilizando a regra de l'hospital
lim x^3+1
x^2-1
x-> -1

Answer 1

Resposta:

Lim   (x³+1)/(x²-1)      ===>  (-1+1)/(1-1) =0/0 , podemos usar L'Hospital

x-->-1

Lim   [d(x³+1)/dx]/ [d(x²-1)/dx]

x-->-1

Lim   (3x²)/(2x)  =3/(-2)=-3/2

x-->-1