Question

use o teorema de Pitágoras para encontrar os valores de x nas figuras abaixo.

Answer 1

a) $x^{2} = 6^{2} +8^{2}$

     $x^{2} = 36+64$

    $x^{2} = 100$$x = \sqrt{100}$

    x=10

b)$10^{2}= x^{2} +6^{2}\\100 = x^{2} +36\\100 - 36 = x^{2} \\x^{2} = 64\\x = \sqrt{64\\ \\\\x = 8$

c) $30^{2} =x^{2} +18^{2}$

   $900 =x^{2} +324$$x^{2} =900 - 324$

   $x^{2} =576$

    $x = \sqrt{576}$

      x = 24

d) $30^{2} =  x^{2} + 24^{2} \\900 = x^{2} + 576\\x^{2} = 900-576\\x^{2} = 324\\x= \sqrt{324}\\ x = 18$

e)$100^{2}=  x^{2} +60^{2} \\10000 = x^{2} + 3600\\x^{2} = 6400\\x = \sqrt{6400} \\x= 80$

f)$25^{2} = x^{2} +20^{2} \\625= x^{2} +400\\x^{2} = 225\\x = \sqrt{225}\\ x=15$