Question

usando o processo de tentativas, encontre a raiz aproximada com uma casa decimal de √20,√17,√10??

Answer 1

√20 = 20+16/ 2.√16 = 36/ 2.4 = 36/8 = 4,5
√17 = 17+16/2,√16 = 33/2.4 = 33/8 = 4,1
√10 = 10+9/2.√9 = 19/2.3 = 19/6 = 3,1
Espero ter ajudado :)

Answer 2

$Ola' \\ \\ \sqrt{20} = \sqrt{16}+ \frac{1}{8} .4 =4+ \frac{1}{2}= \frac{9}{2}=\boxed{4,5 } \\ \\ \sqrt{17}= \sqrt{16}+ \frac{1}{8}.1 =4+ \frac{1}{8}= \frac{33}{8}=\boxed{ 4,125} \\ \\ \sqrt{10}= \sqrt{9}+ \frac{1}{6}.1=3+ \frac{1}{6}= \frac{19}{6}= \boxed{3,16} \\ \\ \\ \mathbb{xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx} \\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Espero~ter~ajudado!!$