Question

usando la formula de bhaskara resuelva :6x 2 -13x=10x-21

Answer 1

Resposta:

x² - 10x + 21 = 0

Δ = b² - 4ac => Δ = (-10)² - 4(1)(21) => Δ = 100 - 84 => Δ = 16

x = -b ± √Δ/2a => x = 10 ± √16/2(1) => x = 10 ± 4/2 => \begin{gathered}x_{1} = \frac{10 + 4 }{2} = > x_{1} = \frac{14 }{2} = > x_{1} = 7 \\x_{2} = \frac{10 - 4 }{2} = > x_{2} = \frac{6 }{2} = > x_{2} = 3\end{gathered}

x

1

=

2

10+4

=>x

1

=

2

14

=>x

1

=7

x

2

=

2

10−4

=>x

2

=

2

6

=>x

2

=3