Question

usando apenas que log2=0,30,log3=0,47e log5=0,69calcule. a)log4. b)log12 c)log25. d)log32. e)log20

Answer 1

a) log4 = log2² = 2log2 = 2 x 0,30 = 0,60
b) log12 = log 2². 3 = log2² + log3 = 2log2 =log3 = 2 x 0,30 + 0.47 =
    0,60 +0,47 = 1,07
c) log25 = log5² = 2log5 = 2 x 0,69 = 1,38
d) log32 = log2¢ = 5log2 = 5 x 0,30 =1,50
e) log20 = log2².5 = log2² + log5 = 2log2 + log5 = 2 x0,30 + 0,69 =                              0,60 + 0,69 = 1,29