Question

Na P.G. (3,6,12), CALCULE

Answer 1

$Formula:An=A1.q^n^-1 A) A8=3.2^7 A8=3.128 A8=384 B) An=A1.q^n^-1 3072=3.2^n^-1 3073/3=2^n^-1 1024=2^n^-1 (Fatorando o 1024 fica assim) 2^1^0=2^n^-1 11=n$