Question

URGENTEEE POR FAVOR
PROVE QUE:

Answer 1

$\dfrac{3}{2} \sqrt{44 + \dfrac{4}{13}} = \sqrt{99 + \dfrac{9}{13}} \\ \\ \\ \dfrac{3}{2} \sqrt{\dfrac{44 * 13 + 4}{13}} = \sqrt{ \dfrac{99 * 13 + 9}{13}} \\ \\ \\ \dfrac{3}{2} \sqrt{\dfrac{576}{13}} = \sqrt{ \dfrac{1296}{13}}$

$\dfrac{3}{2} \sqrt{\dfrac{2^6 * 3^2}{13}} = \sqrt{ \dfrac{2^4 * 3^4}{13}} \\ \\ \\ \dfrac{3}{2} *{\dfrac{ \sqrt{13} *2^3*3}{13}} = { \dfrac{ \sqrt{13} * 2^2 * 3^2}{13}} \\ \\ \\ \dfrac{3}{2} *{\dfrac{ 24\sqrt{13}}{13}} = { \dfrac{ 36\sqrt{13}}{13}}$

$mmc \ de \ 13, 2 = 26 \\ \\ \\ \dfrac{ 3 * 24\sqrt{13}}{26}} = { \dfrac{ 36\sqrt{13}}{13}} \\ \\ \\ \dfrac{ 72\sqrt{13}}{26}} = { \dfrac{ 36\sqrt{13}}{13}} \\ \\ \\ \\ => { \dfrac{ 36\sqrt{13}}{13}} = { \dfrac{ 36\sqrt{13}}{13}}$