Question

URGENTEEE !!!!!! Calcule a área total da superficie de uma pirâmide triangular regular cuja aresta lateral mede 82 mm e aresta da base mede 36mm.

Answer 1

A area da base :
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dados :
>>>>>>>
aresta lateral = 82mm
aresta da base = 36mm

Sb = a^2 *\/3
........._______
..................4

Sb = (36)^2 *\/3
.........________
...................2

Sb = 1.296*\/3
........._______
.................4

Sb = 324*\/3 mm^2


Apotema do piramide
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(Apot.)^2 = L^2 - (a/2)^2

(Apot.)^2 = (82)^2 - (36/2)^2

(Apot.)^2 = 6.724 - (18)^2

(Apot.)^2 = 6.724 - 324

(Apot.)^2 = 6.400

Apot. = \/6.400

Apot. = 80mm


A area latetal (Al) :
#############
Al = 3 * a * Apot.
........_________
.................2

Al = 3 * 36 * 80
........_________
...................2

Al = 108 * 80
........_______
................2

Al = 8.640
......._____
............2

Al = 4.320mm^2


A area total (At) :
#############
At = Al + Ab

At = 4.320 + 324*\/3mm^2