Question

Urgente

Expressão Trigonométrica

Y = sen π/3 rad – 2.sen π/6 rad
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    Sen 3π/2 rad – 3.sen π/2 rad

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Answer 1

$\sf{y=\dfrac{sen\left(\dfrac{\pi}{3}\right)-2\cdot sen\left(\dfrac{\pi}{6}\right)}{sen\left(\dfrac{3\pi}{2}\right)-3\cdot sen\left(\dfrac{\pi}{2}\right)}}\\\sf{y=\dfrac{\dfrac{\sqrt{3}}{2}-2\cdot\dfrac{1}{2}}{-1-3\cdot1}}\\\sf{y=\dfrac{\dfrac{\sqrt{3}-2}{2}}{-4}}$

$\sf{y=\left(-\dfrac{1}{4}\right)\cdot\left(\dfrac{\sqrt{3}-2}{2}\right)}\\\sf{y=-\dfrac{\sqrt{3}-2}{8}}$

Answer 2

Oie, Td Bom?!

$y = \frac{ \sin( \frac{\pi}{3} ) - 2 \sin( \frac{\pi}{6} ) }{ \sin( \frac{3\pi}{2} ) - 3 \sin( \frac{\pi}{2} ) }$

$y = \frac{ \frac{ \sqrt{3} }{2} - 2 \: . \: \frac{1}{2} }{ - 1 - 3 \: . \: 1}$

$y = \frac{ \frac{ \sqrt{3} }{2} - 2 \: . \: \frac{1}{2} }{ - 1 - 3}$

$y = \frac{ \frac{ \sqrt{3} }{2} - 1}{ - 4}$

$y = \frac{ \frac{ \sqrt{3} - 2}{2} }{4}$

$y = - \frac{ \frac{ \sqrt{3} - 2 }{2} }{4}$

$y = - \frac{ \sqrt{3} - 2 }{8}$

Att. Makaveli1996