Question

URGENTE!!!!
(deixe as resoluções por favor!!!)
Calcule:

A)-√¯100-³√¯64=

B)-³√¯125-³√¯-1=

C)^{5}√¯1+√¯9-³√¯8=

D)√¯100+^{5}√¯-32+^{6}√¯0=

E)^{4}√¯16+^{7}√¯1-^{5}√¯-1

Answer 1

A)
$- \sqrt{100} - \sqrt[3]{64} =- \sqrt{2^2.5^2} - \sqrt[3]{2^6} =-10-2^2=-10-4=-14$

B)
$- \sqrt[3]{125} - \sqrt[3]{-1} =- \sqrt[3]{5^3} - \sqrt[3]{-1} =-5-(-1)=-5+1=-4$

C)
$\sqrt[5]{1} + \sqrt{9} - \sqrt[3]{8} =1+ \sqrt{3^2} - \sqrt[3]{2^3} =1+3-2=4-2=2$

D)
$\sqrt{100} + \sqrt[5]{-32} + \sqrt[6]{0} = \\ \\ \sqrt{2^2.5^2} + \sqrt[5]{-2^5} +0= \\ \\ 10+(-2)+0=10-2=8$

E)
$\sqrt[4]{16} + \sqrt[7]{1} - \sqrt[5]{-1} = \\ \\ \sqrt[4]{2^4} +1-(-1)= \\ \\ 2+1+1=4$