Question

urgente
A forma trigonométrica de r(3) + i é: *Considere r(3) como a raiz quadrada de 3.
cos30° + i.sen30°
2(cos60° + i.sen60°)
cos60° + i.sen60°
2(cos30° + i.sen30°)

Answer 1

$z=\sqrt3+i\\ \\ \rho=|z|=\sqrt{(\sqrt3)^2+1^2}= \sqrt{4}=2 \\ \\ sen \theta=\frac{b}{\rho}=\frac{1}{2}\\ \\ cos \theta=\frac{a}{\rho}=\frac{\sqrt3}{2}\\ \\ \theta=\frac{\pi}{6} \ rad\\ \\ \boxed{z=2[cos(\frac{\pi}{6})+isen(\frac{\pi}{6})]}$

Lembre-se que π/2 rad = 30°