Question

(Unicid-SP) se f(2x-3)=3x²-4x+2, o valor de f(1) vale:
A) 0
B) 1
C) 3
D) 6
E) 9

Answer 1

f(1) - 2x-3 = 1
        2x=1+3
        x = 4/2 = 2

f(1) - 3.2² - 4.2 + 2 = 12-8+2 = 6 D

Answer 2

 Olá Henrique,

Façamos,

2x - 3 = 1
2x = 1 + 3
2x = 4
x = 2

 Portanto,

$f(2x-3)=3x^2-4x+2\\f(2\cdot2-3)=3\cdot(2)^2-4\cdot(2)+2\\f(4-3)=12-8+2\\\boxed{f(1)=6}$