Question

uma pessoa ,correndo ,percorre 4,0 km com velocidade escalar de 12 km/h. o tempo do percurso é de ?

Answer 1

$Dados:\\ S\longrightarrow 400 km \\Vm\longrightarrow 12 km/h\\\\Resposta:\\\\Vm=\frac{\Delta S}{\Delta t} \\\\12=\frac{4}{t} \\\\Passaremos-o -Tempo-para-o-lugar-da-velociade\\\\t=\frac{4}{12} \\\\t=0,33 horas$

Answer 2

$\large{\begin{array}{l}\sf V=\dfrac{\Delta S}{\Delta t}\Rightarrow\Delta t=\dfrac{\Delta S}{V}\\\\\sf \Delta t=\dfrac{4}{12}\\\\\boxed{\boxed{\sf \Delta t\approx0{,}333\,h}}\leftarrow\textsf{tempo em horas}\\\\\sf 1\,h\rightarrow60\,min\\\sf 0{,}333\,h\rightarrow t\\\\\sf t=\dfrac{60\cdot0{,}333}{1}\\\\\boxed{\boxed{\sf t\approx 20\,min}}\leftarrow\textsf{tempo em minutos}\end{array}}$