Question

Um vendedor aplicou 12.000,00 a juros compostos, durante dois anos, a taxa de 1,5% a.m. qual o valor do juros recebidos? 

Answer 1

Temos que mudar a taxa, passar de mensal para anual.

i = 1,5% a.m. = i = 18% a.a.

$\boxed{M = C(1+i)^t}\\\\ M = 12000(1+0,18)^2\\\\ M = 12000(1,18)^2\\\\ M = 12000(1,3924)\\\\ \boxed{M=16708,8}$

$\boxed{M=J+C}\\\\ 16708,8= J+12000\\\\ J=16708,8-12000\\\\ \boxed{J=4708,8}$

Answer 2

formula juros composto
$M=P*(1+i) ^{n}$

$ONDE:$
$M=Montante$
$P=capital$
$i=Taxa$
$n=Tempo$

 $temos:$

 $m=?$
$p=12.000,00$
$i=1,5a.m(1,5*12=18)(18/100=0,18)$
$t=2 anos$
  
$M=12000*(1+0,18) ^{2}$
$M=12000*(1,18) ^{2}$
$M=12000*1,3924$
 $M=16708,80$

$J=M-P$
$J=16708,80-12000$
$J=4708,80$