Question

Um sarrafo de madeira (Alfa = 5.10-6 ºC-1 ) tem comprimento de 10m a 20ºC. Que comprimento terá a 70ºC.

Answer 1

$\Delta L=L_{0}. \alpha .\Delta \theta\\\\\Delta L=10.(5.10^-^6).(70-20)\\\\\Delta L=2,5.10^-^3=0,0025\\\\L=L_{0}+\Delta L=>L=10+0,0025=>L=10,0025m$