Question

ufac o valor da expressão numérica 2-{1/2:4-0[5+(2²:0,333...)]}

Answer 1

Olha;
{1/2÷4-0 [5+(2^2÷0,333...)]}
{1/2÷4-0}
*Porque ao multiplicar por 0, tudo ira virar zero.
{1/2×1/4-0}
{1/8-0}
{0.125-0}
0.125 ou 1/8

Answer 2

$\ \ \ 2-\{ \frac{1}{2}:4-6^0+[5+(2^2 : 0,333...)] \}\\ \\= 2- \{ \frac{1}{2}\cdot \frac{1}{4} -1+[5+(4 : \frac{3}{9} )] \}\\ \\= 2- \{ \frac{1}{8}-1+[5+(4 \cdot \frac{9}{3} )] \}\\ \\= 2- \{ \frac{1}{8}-1+[5+12] \}\\ \\= 2- \{ \frac{1}{8}-1+17 \}\\ \\= 2- \{ \frac{1}{8}-\frac{8}{8}+\frac{136}{8} \}\\ \\= 2- \{\frac{1-8+136}{8} \}\\ \\= 2- \frac{129}{8} \\ \\= \frac{16}{8} - \frac{129}{8} \\ \\= \frac{16-129}{8} \\ \\= -\frac{113}{8}$